Hello, I am a physics undergraduate student using FastCap2 for my project works. I am having problems on how to find the capacitance between 2 square capacitor of 10 cm and a distance of 1 mm separating them. The permissivity being #949;_0. Can somebody please help?

When you open FastCap2 (GUI version for Windows) or FasterCap, just go to the 'Help' menu and select 'Help topics'

Best, Enrico

Thank you so far for your help dear Enrico but I am still having difficulties to navigate my way through FastCap. Could you please help me in my work to generate the Capacitance Matrix for 2 square capacitors each of length 10 cm and width of 10 cm and separated by a distance of 1 mm? #949; = #949;_o.

I report here the parallel plate simple capacitor example to be used in FasterCap:

File "capacitor_simple.lst"

* Simple parallel plate capacitor
*
*
* This capacitor is made by two square metal contacts
* embedded in an homogeneous dielectric medium
*
* If fringing fields are neglected, the capacitance as per analytical formula
* is e0*er*S/d where S is the surface of the armors and d is their distance.
* In this case S = 1, d = 0.01, er = 1, therefore C = 8.854e-12 * 1 * 1 / 0.001 = 8.854e-9
*
* Remark: given the high geometrical ratio 1:1000 between the plate side and
* the plate distance, for proper solution convergence you need to set FasterCap's
* '-d' parameter to 0.1 or lower values.
*
*
* lower contact
C plate.txt 1.0 0.0 0.0 0.0
* upper contact
C plate.txt 1.0 0.0 0.0 0.001

I report here the parallel plate simple capacitor example to be used in FasterCap:

File "capacitor_simple.lst"

* Simple parallel plate capacitor
*
*
* This capacitor is made by two square metal contacts
* embedded in an homogeneous dielectric medium
*
* If fringing fields are neglected, the capacitance as per analytical formula
* is e0*er*S/d where S is the surface of the armors and d is their distance.
* In this case S = 1, d = 0.01, er = 1, therefore C = 8.854e-12 * 1 * 1 / 0.001 = 8.854e-9
*
* Remark: given the high geometrical ratio 1:1000 between the plate side and
* the plate distance, for proper solution convergence you need to set FasterCap's
* '-d' parameter to 0.1 or lower values.
*
*
* lower contact
C plate.txt 1.0 0.0 0.0 0.0
* upper contact
C plate.txt 1.0 0.0 0.0 0.001

For your case, you need to modify the plate.txt to be 0.1m x 0.1m instead of 1m x 1m; separation is already 1mm.

Mind the node in the comments about the -d parameter.

Best Regards, Enrico

Hello once again Dear Enrico, When I am trying to run the algorithm you provided in the reply the following is appearing:

Running fastcap 2.0 (18Sep92) Input: C:\Users\Farook Soopun\Documents\capacitor_simple.lst No title line beginning with '0' found, assuming PATRAN input file zero element request in file `fastcap\patran.c' at line 143

Dear enrico, Thank you for your precious help. I wanted to that while using fastercap can only use the provided algorithm or can i write my own algorithm also?