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bruce
1 Posts |
 Posted - May 29 2009 : 07:50:10
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I have a question about how the self/auto-capacitances (i.e. contribution to the diagonal terms in the capacitance matrix) relate when you add more conductors.
When you have a conductor in free space, it has some self-capacitance Csum. When you add another conductor to the universe, the diagonal entry in the capacitance matrix becomes Ctotal = C11+C12.
What is the relationship between Csum and C11? Does Csum=C11?
Hope someone can help,
Bruce |
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dileesh
India
2 Posts |
Posted - Jun 11 2009 : 11:00:07
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hi...
Check this link ..It may help you
ht*p://w*w.freelists.org/post/si-list/nonnegative-off-diagonal-capacitive-matrix-elements,10
Dileesh |
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Enrico
550 Posts |
Posted - Jun 17 2009 : 00:32:21
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Though it may happen that you have non-negative off-diagonal entries in the capacitance matrix from a field solver, usually due to round-off errors or inaccuracies of the SW, I think this is not the answer you were looking for.
The short answer is, the output matrix from FastCap2 is a Maxwell capacitance matrix. You can find further information and long explanation on how this matrix is formed under the topic "How to make a conductor" in this FastCap forum
I may add also that if you have, say, a conductor composed by two elements, then defining C1 self-capacitance of first element, C2 self-capacitance of the second element, Cm the mutual capacitance between the two, then the overall capacitance of the conductor (if the two elements are then somehow shorted together) is C1+C2
Hope this helps!
Best Regards,
Enrico
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Self-capacitance with multiple conductors
