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SciL
2 Posts |
Posted - Jan 17 2016 : 08:11:14
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Hi fellows, I am a new user of FastHenry2. I am now trying to calculate the mutual inductance between two conductors at DC case. I finished the modelling of two line conductors, the code is: *Test model .unit m .Default z=0 sigma=5.8e7 *N1&N2 make line1, N3&N4 make line2 *Both lines are 10 long *Separated by 1 N1 x=0 y=0 N2 x=10 y=0 N3 x=10 y=5 N4 x=20 y=5 E1 N1 N2 w=0.1 h=0.1 E2 N3 N4 w=0.1 h=0.1 .external n1 n2 .external n3 n4 .freq fmin=0 fmax=0 .end
And the result shows: Computed matrices (R+jL) Row 0: n1 to n2 Row 1: n3 to n4 Freq = 0 Row 0: 1.72414e-005+0j -0+0j Row 1: -0+0j 1.72414e-005+0j
I do not really understand the result.
How to calculate the mutual inductance exactly?
Thanks in advance.
Regards. |
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Enrico
545 Posts |
Posted - Jan 18 2016 : 18:10:55
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You cannot calculate the inductance in perfectly static conditions, as the magnetic fields are created by the moving charges (and FastHenry does not allow using magnets). You need to set the frequency to a small value, e.g. 1 Hz, to see you results. Usually the low value is chosen to be low enough for the skin effect to play no role, but not too low to avoid any numerical issue (e.g. do not set the frequency to 1E-20 Hz, etc.)
The user's manual, as well as the sample files, provide some examples.
Best Regards, Enrico
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SciL
2 Posts |
Posted - Jan 19 2016 : 05:55:59
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Well noted. I found the example given by the manual and my problem has been solved. Thank you for your guide.
Best regards
quote: Originally posted by Enrico
You cannot calculate the inductance in perfectly static conditions, as the magnetic fields are created by the moving charges (and FastHenry does not allow using magnets). You need to set the frequency to a small value, e.g. 1 Hz, to see you results. Usually the low value is chosen to be low enough for the skin effect to play no role, but not too low to avoid any numerical issue (e.g. do not set the frequency to 1E-20 Hz, etc.)
The user's manual, as well as the sample files, provide some examples.
Best Regards, Enrico
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