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 Do Dielectrics have to be closed surfaces

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chgad Posted - Aug 12 2019 : 15:56:17

conductors have to be closed Surfaces. Is this also the case for dielectrics ?


I have 2 conductor strips (some distance apart)on a SiO2 layer. The dielectric layer is below botth stribs (e.g. z<0), the strips both in x-y-plane.

I create the conductor strips (Cuboids) by 3 Q panels with outperm 1.0 and 1 Q panel with outperm 3.9 each, join them in a List file.

Now i want to add the dielectric layer.
Is it now enough to implement the layer as a few Q panels in the x-y-plane surounding the 2 Metal strips or do i have to make a Cuboid expanding in z-direction.

To be pricise:

Only panels in x-y-plane: ht*ps://

Cuboid as dielectric : ht*ps://

Or did i miss something in the Docs ?

Thanks in advance.
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chgad Posted - Aug 13 2019 : 12:20:50
Thank you.

The Question arose concerning the question : "Is my Input faulty defined?"

Enrico Posted - Aug 12 2019 : 23:10:04
In your case, both options may be good, if the dielectric surface is large and thick. In the case of a dielectric represented as a 2D object and not a 3D cuboid, it should be large enough to have a negligible effect on the fringing fields (in your pictures it seems large enough, but you can see the effect only by simulation).

Best Regards,

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