All Forums  FastFieldSolvers  FasterCap and FastCap2  Dielectric interface

Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!

Screensize: 640 x 480 800 x 600 1024 x 768 1280 x 1024 UserName: Password: Antispam question: What do MOONwalk and MOONdance have in common? Answer: Format Mode: Basic  Help  Prompt  Format: Font Andale Mono Arial Arial Black Book Antiqua Century Gothic Comic Sans MS Courier New Georgia Impact Lucida Console Script MT Bold Stencil Tahoma Times New Roman Trebuchet MS Verdana   Size 1 2 3 4 5 6   Color Black Red Yellow Pink Green Orange Purple Blue Beige Brown Teal Navy Maroon LimeGreen Message: * HTML is OFF * Forum Code is ON [quote][i]Originally posted by Annda[/i] [br]Okay, so I have this problem but first of all, I am not so sure I understand correctly how to use the dielectric. So I am trying this example where I have a coaxial cable and the space between the two cylindrical conductors of radii a and c is filled with two homogeneous dielectrics of #949;1 and #949;2. The interface between the two dielectrics is of radius b. I made three .qui file using Matlab and created three cylinders each with length 10m and with radii 2.5, 5m and 7.5m. The code I used in the .lst file is this: * C cylinder3.qui 1 0.000 0.000 0.000 D cylinder4.qui 2 1 0.000 0.000 0.000 0.000 0.000 0.000- C cylinder5.qui 1 0.000 0.000 0.000 To understand if I got this clear the second line shows that I am using a dielectric and the inner side has the permittivity 1 and the outer side of the dielectric has the permittivity 2. Then there are the coordinates in which the second cylinder is placed and the other part says that the point (0.0, 0.0, 0.0) is in the medium with the dielectric medium of 1. When I used the in the second line 1 before 2 I got a warning. This is how I understood the line. The result I get is C12=C21=0.5704nF. Using Gauss law doing this example I got the result C=0.6207nF. Now the problem I seem to have is that when I run this in FasterCap I get this result: Dimension 2 x 2 g1_1 8.07306e-010 -4.23448e-010 g2_1 -7.21873e-010 1.17276e-009. Which means that C12 is not the same as C21. Anndaa [/quote]   Check here to include your profile signature.